“…Thus, (1) will be equal to: m EX (Explainable(E1, [15,22], ∅) = {1 × m GN (Genuine(C 111 , [15,22],{Φ 11 })} + {1×{m GN (Genuine(Φ 12 , [15,22], {Φ 12 })) + m GN (Genuine(C 121 , [15,22], {Φ 12 })) -m GN (Genuine(Φ 12 , [15,22],{Φ 12 })) × m GN (Genuine(C 121 , [15,22],{Φ 12 }))} − {1× m GN (Genuine(C 111 , [15,22],{Φ 11 })} × {1×{m GN (Genuine(Φ 12 , [15,22], {Φ 12 })) + m GN (Genuine(C 121 , [15,22], {Φ 12 })) -m GN (Genuine(Φ 12 , [15,22],{Φ 12 })) × m GN (Genuine(C 121 , [15,22],{Φ 12 }))} (2) Note, however, as there are no recorded events that can be unified with C 111 and C 121 in the event log, we have: m GN (Genuine(C 111 , [15,22],{Φ 11 })) = 0 m GN (Genuine(C 121 , [15,22],{Φ 12 })) = 0 Thus, (2) becomes: m EX (Explainable(E1, [15,22], ∅) = m GN (Genuine(Φ 12 , [15,22], {Φ 12 }))) (3) E2, however, can be unified with Φ 12 and EXP E2 = {E NULL }. Thus, we will have m GN (Genuine(Φ 12 , [15,22],{Φ 11 })) = m IL (Occurred(E2)) × m EX (Explainable(E2)) = α 2 Therefore, it will be m EX (Explainable(E1, [15,22]…”