“…It should be noted that the reactivity of (C 5 H 5 ) 3 NpCl with alkyl lithium reagents does form as ignificant amount of (C 5 H 5 ) 3 Np III ,w hich is not unexpected given the Np(IV/III) redox couple. [23] Recently,G aunt and co-workers reported NpCl 4 (DME) 2 , [25] NpCl 4 (THF) 3 ,a nd NpCl 3 (pyridine) 4 , [26] which has replaced NpI 3 (THF) 4 , [27] as au seful neptunium starting materials since neptunium metal is required to prepare NpI 3 (THF) 4 .H ere,w er eport the synthesis of as table transuranic hydrocarbyl complex, Np[h 4 -Me 2 NC-(H)C 6 H 5 ] 3 ,d irectly from NpCl 4 (DME) 2 ,c ircumventing the need for an alkali-metal reducing agent. [26] This work is analogous to our recent synthesis of au ranium(III) hydrocarbyl complex, U[h 4 -Me 2 NC(H)C 6 H 5 ] 3 ,f rom reaction with UCl 4 .…”