“…Ar = 2,6-diisopropylphenyl, Ar' = 3,5-(CF 3 ) 2 C 6 H 3 . (7), O(1)-Ni(1) 1.904 (5), C(3)-C(1) 1.538 (9), O(1)-Al(1) 1.806 (5), Al(1)-N(1) 1.972(6), N(1)-C(1) 1.278 (7); Ni(1)-N(2)-C(2) 118.1 (5), N(2)-C (2) are well-established, [16] the reaction with TEA and subsequent formation of complex 5 proceeds with the elimination of ethylene, as evidenced by the 1 H NMR spectrum (d = 5.4 ppm in CD 2 Cl 2 at 210 K), probably through direct bhydrogen transfer to the coordinated carbonyl group. [16,17] Comparison of the structural features of 4 and 5 shows that the bulkier ethyl groups in 5 result in a more crowded coordination plane at the nickel center (Figures 2 and 3).…”