“…Consider the BVP(6.4) − u ′′ (t) + u(t) = λte u(t) , t ∈ [0, 1], u ′ (0) = u ′ (1) = 0.In[3] the authors establish the existence of at least one positive solution such that u < 2 for λ ∈ (0, 2e −2 ).The BVP (6.4) is equivalent to the following integral problemu(t) = k(t, s)g(s)f (u(s))ds, where g(s) = s, f (u) = λe u − t) cosh s, 0 ≤ s ≤ t ≤ 1, cosh(1 − s) cosh t, 0 ≤ t ≤ s ≤ 1.The kernel k is positive, by the results Section 5 satisfies (C 1 )-(C 8 ) with [a, b] = [0, 1]. Thus we work in the cone K = {u ∈ C[0, 1] : min t∈[0,1] u(t) ≥ c u }, where c = c(0, 1) = 1/ cosh 1 = 0.648.We can compute the following constants ρ =f ρ,ρ/c = λe ρ /ρ.…”