The platform will undergo maintenance on Sep 14 at about 9:30 AM EST and will be unavailable for approximately 1 hour.
2020
DOI: 10.48550/arxiv.2006.14460
|View full text |Cite
Preprint
|
Sign up to set email alerts
|

Natural families in evolution algebras

Abstract: In this paper we introduce the notion of evolution rank and give a decomposition of an evolution algebra into its annihilator plus extending evolution subspaces having evolution rank one. This decomposition can be used to prove that in non-degenerate evolution algebras, any family of natural and orthogonal vectors can be extended to a natural basis. Central results are the characterization of those families of orthogonal linearly independent vectors which can be extended to a natural basis.We also consider ide… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
2
1

Citation Types

0
9
0

Year Published

2021
2021
2021
2021

Publication Types

Select...
1

Relationship

0
1

Authors

Journals

citations
Cited by 1 publication
(9 citation statements)
references
References 5 publications
0
9
0
Order By: Relevance
“…A useful criterion for an element z of A with z 2 = 0 to be natural (i.e. embeddable in a natural basis) is that dim(span({e 2 i : i ∈ supp(z)})) = 1 (see [1,Teorema 3.3]). We recall that an evolution algebra A is non-degenerate if there exists a natural basis {e i } such that e 2 i = 0 for every i.…”
Section: Preliminariesmentioning
confidence: 99%
See 4 more Smart Citations
“…A useful criterion for an element z of A with z 2 = 0 to be natural (i.e. embeddable in a natural basis) is that dim(span({e 2 i : i ∈ supp(z)})) = 1 (see [1,Teorema 3.3]). We recall that an evolution algebra A is non-degenerate if there exists a natural basis {e i } such that e 2 i = 0 for every i.…”
Section: Preliminariesmentioning
confidence: 99%
“…With this in mind, we have Proposition 2.4. Let A be a non-degenerate evolution algebra, then (1) Let B = {e i } i∈Λ be a natural basis of A. If z, z ′ are different elements such that zz ′ = 0, then supp(z) ∩ supp(z ′ ) has cardinal different from 1 (supports relative to B).…”
Section: Preliminariesmentioning
confidence: 99%
See 3 more Smart Citations