2018
DOI: 10.1214/17-aap1353
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Mutations on a random binary tree with measured boundary

Abstract: Consider a random real tree whose leaf set, or boundary, is endowed with a finite mass measure. Each element of the tree is further given a type, or allele, inherited from the most recent atom of a random point measure (infinitelymany-allele model) on the skeleton of the tree. The partition of the boundary into distinct alleles is the so-called allelic partition.In this paper, we are interested in the infinite trees generated by supercritical, possibly time-inhomogeneous, binary branching processes, and in the… Show more

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Cited by 5 publications
(9 citation statements)
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“…Let (d ij ; i, j ≥ 1) and (Y i ; i ≥ 1) be an exchangeable marked ultrametric matrix. There exists a random marked probability UMS [U, d, U , µ] (that is, µ(U ) = 1 a.s.) such that the exchangeable marked ultrametric matrix obtained by sampling from it as in (11) is distributed as (d ij ; i, j ≥ 1) and (Y i ; i ≥ 1). Moreover this marked UMS is unique in distribution.…”
Section: An Ultrametric On N;mentioning
confidence: 99%
“…Let (d ij ; i, j ≥ 1) and (Y i ; i ≥ 1) be an exchangeable marked ultrametric matrix. There exists a random marked probability UMS [U, d, U , µ] (that is, µ(U ) = 1 a.s.) such that the exchangeable marked ultrametric matrix obtained by sampling from it as in (11) is distributed as (d ij ; i, j ≥ 1) and (Y i ; i ≥ 1). Moreover this marked UMS is unique in distribution.…”
Section: An Ultrametric On N;mentioning
confidence: 99%
“…It can be shown [8] that the boundary of (τ f ,d f ) is indeed (Ī,d f ), which explains why we keep the same notation for the two distances. Also that for each t ∈ I, L t = ρ, α t , where α t ∈Ī is equal to (t, r).…”
Section: The Comb Metricmentioning
confidence: 99%
“…Proof. We know from [8] that ϕ(t) is the genealogy of a reversed (i.e. time flows from T to 0) pure-birth tree with birth rate β = β • ϕ −1 .…”
Section: The Boundary Of a Pure-birth Processmentioning
confidence: 99%
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