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2011
DOI: 10.1109/twc.2011.060811.100582
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Multiple-Differential Encoding for Multi-Hop Amplify-and-Forward IR-UWB Systems

Abstract: In this paper, we propose a novel multi-hop relaying scheme to improve the performance and coverage of impulseradio-based ultra-wideband (IR-UWB) systems. With regard to a simple practical realization, we focus on a non-coherent system setup in conjunction with amplify-and-forward (A&F) relaying. In particular, we propose to employ a multiple-differential encoding scheme at the source node and single differential decoding at each relay and at the destination node, respectively, so as to efficiently limit inter… Show more

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Cited by 14 publications
(28 citation statements)
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References 25 publications
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“…We focus on the channel model CM1, considering a path loss exponent p = 3 and a standard deviation of the log-normal fading term σ fad = 2.5. The number of frames used to transmit each symbol is N f = 2, the bandwidth of bandpass filter is W = 5 GHz, and the integration time is Ti = 5.25 ns [10]. Let d sd , dsr and d rd be the source-destination, source-relay, and relay-destination distances.…”
Section: Numerical Resultsmentioning
confidence: 99%
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“…We focus on the channel model CM1, considering a path loss exponent p = 3 and a standard deviation of the log-normal fading term σ fad = 2.5. The number of frames used to transmit each symbol is N f = 2, the bandwidth of bandpass filter is W = 5 GHz, and the integration time is Ti = 5.25 ns [10]. Let d sd , dsr and d rd be the source-destination, source-relay, and relay-destination distances.…”
Section: Numerical Resultsmentioning
confidence: 99%
“…In addition, even if SNRc depends on Eg/N0, we notice that the power allocation strategy is slightly affected by changes in this ratio. Figures 2 and 3 present a performance comparison between the direct transmission with single differential encoding, A&F noncooperative relaying with double differential encoding and the power allocation strategy described in [10], and the proposed cooperative approach with αs = 0.5 (equal power allocation) and αs given by Eq. (19).…”
Section: Numerical Resultsmentioning
confidence: 99%
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