1963
DOI: 10.1215/s0012-7094-63-03028-x
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Modulary groups of t×t matrices

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Cited by 47 publications
(77 citation statements)
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“…This Lorentz transformation freedom may be viewed as providing a choice of "inertial frame" normalisation at each radius, and may be used to normalise certain of the remaining metric coefficients, as described below. This interpretation is supported by a comparison [9] between the Robinson-Trautman metrics and the NU form [10] of the Minkowski metric in coordinates using null cones with base point describing a timelike curve. This comparison may also be made in the NQS coordinates, and supports both the interpretation of Robinson-Trautman spacetimes as describing an accelerated black hole rapidly settling down to a Schwarzschild black hole in uniform motion, and the interpretation of the NQS freedom as representing a choice of reference frame at each radius and time.…”
Section: Introductionmentioning
confidence: 88%
“…This Lorentz transformation freedom may be viewed as providing a choice of "inertial frame" normalisation at each radius, and may be used to normalise certain of the remaining metric coefficients, as described below. This interpretation is supported by a comparison [9] between the Robinson-Trautman metrics and the NU form [10] of the Minkowski metric in coordinates using null cones with base point describing a timelike curve. This comparison may also be made in the NQS coordinates, and supports both the interpretation of Robinson-Trautman spacetimes as describing an accelerated black hole rapidly settling down to a Schwarzschild black hole in uniform motion, and the interpretation of the NQS freedom as representing a choice of reference frame at each radius and time.…”
Section: Introductionmentioning
confidence: 88%
“…different ways. To prove the last part of the theorem we observe that, if 2 and these are equal, by (3). If C is a common transversal, we have…”
Section: A Well-known Theorem In Group Theorymentioning
confidence: 93%
“…In particular, M. Newman [5] and D. JVlcQuillan [4] have shown that if Γ(n) C G CΓ (1), (n, 6) = 1, then G = Γ(d) or Γ(d) where d \ n. The only additional result that we need is (2.1) f(n)Γ(k) = Γ(l), (n,fc)=l, which was proved by M. Newman and J. R. Smart in [6].…”
mentioning
confidence: 84%
“…is an element of G(ra (1/2) )' but is certainly not an element of Γ 2 (8) when m = 2 or Γ 3 (6) when m = 3.…”
Section: Classification Theorems For Normal Congruence Subgroupsmentioning
confidence: 99%