1996
DOI: 10.1103/physrevd.53.1537
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Abstract: With µ → eγ decay forbidden by multiplicative lepton number conservation, we study muonium-antimuonium transitions induced by neutral scalar bosons. Pseudoscalars do not induce conversion for triplet muonium, while for singlet muonium, pseudoscalar and scalar contributions add constructively. This is in contrast to the usual case of doubly charged scalar exchange, where the conversion rate is the same for both singlet and triplet muonium. Complementary to muonium conversion studies, high energy µ + e − → µ − e… Show more

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Cited by 19 publications
(22 citation statements)
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References 30 publications
(32 reference statements)
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“…where Γ μ ¼ m 5 μ G 2 F =192π 3 ≈ 3 × 10 −10 eV is the muon decay rate. The evaluation of the (singlet) matrix element gives [56]…”
Section: E Heavy Np and Lfv Effectsmentioning
confidence: 99%
“…where Γ μ ¼ m 5 μ G 2 F =192π 3 ≈ 3 × 10 −10 eV is the muon decay rate. The evaluation of the (singlet) matrix element gives [56]…”
Section: E Heavy Np and Lfv Effectsmentioning
confidence: 99%
“…Usually these experiments apply only when the leptonic mixing matrix is diagonal [14]. Also, in models with extended Higgs sector some not unrealist situations could exist in which scalar bosons contribution to muonium to antimuonium conversion is not negligible [15]. Therefore, in this work we assume a more interesting lower limit on the double charged bilepton mass, ∼ 350 GeV, which is accessible to next generation of accelerators and is compatible with others low energy bounds [9,16].…”
Section: Introductionmentioning
confidence: 99%
“…The interactions in Eqs. (2) and (7) involve different mixing matrices, hence, if all bosons have masses of the same order of magnitude, as it is in fact expected in the 331 model (see below), we can have some cancellations among all the contributions. Notice that those matrices are unitary only when G ′ is real, like the matrices in Eq.…”
mentioning
confidence: 69%
“…In this case the neutral currents given in Eq. (7) are diagonal and there is no FCNC in the lepton sector and all the sextet-lepton couplings are proportional to K RL = √ 2m l /v S where m l is the lepton mass. If v S is of the order of 100 GeV the main contribution to the M → M conversion comes from the interaction in Eq.…”
mentioning
confidence: 99%