2015
DOI: 10.1016/j.jde.2014.10.013
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L1limit solutions for control systems

Abstract: Abstract. For a control Cauchy probleṁgα(x)uα, x(a) =x, on an interval [a, b], we propose a notion of limit solution x, verifying the following properties: i) x is defined for L 1 (impulsive) inputs u and for standard, bounded measurable, controls v; ii) in the commutative case (i.e. when [gα, g β ] ≡ 0, for all α, β = 1, . . . , m), x coincides with the solution one can obtain via the change of coordinates that makes the gα simultaneously constant; iii) x subsumes former concepts of solution valid for the gen… Show more

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Cited by 18 publications
(77 citation statements)
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“…Definition 2.2. We call a feasible strict-sense process (T ,ū,ā,x,v) a local strict-sense minimizer of (P) if there exists δ > 0 such that for every feasible strict-sense process (T, u, a, x, v) verifying d (T, x, v), (T ,x,v) < δ, where d is the distance defined in (5). If relation (7) is satisfied for all feasible strict-sense processes, we say that (T ,ū,ā,x,v) is a global strict-sense minimizer.…”
Section: The Optimization Problemsmentioning
confidence: 99%
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“…Definition 2.2. We call a feasible strict-sense process (T ,ū,ā,x,v) a local strict-sense minimizer of (P) if there exists δ > 0 such that for every feasible strict-sense process (T, u, a, x, v) verifying d (T, x, v), (T ,x,v) < δ, where d is the distance defined in (5). If relation (7) is satisfied for all feasible strict-sense processes, we say that (T ,ū,ā,x,v) is a global strict-sense minimizer.…”
Section: The Optimization Problemsmentioning
confidence: 99%
“…Let us call equivalent any two space-time processes (S,w 0 ,w,α,ỹ 0 ,ỹ,β), (S, w 0 , w, α, y 0 , y, β) as above. The following result is quite straightforward: 5 Since every L 1 -equivalence class contains Borel measurable representatives, we tacitly assume that all L 1 -maps we are considering are Borel measurable when necessary.…”
Section: The Optimization Problemsmentioning
confidence: 99%
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“…and (ȳ 0 ,ȳ,ν) = (ȳ 0 ,ȳ 1 ,ȳ 2 ,ȳ 3 ,ν) = (s, 1, 0, 0, 0)χ [0,1] + (1, 2 − s, 0, 0, s − 1)χ [1,2] ,…”
Section: Examplesmentioning
confidence: 99%
“…(s) = 0, dp 2 ds (s) = −p 2 (s)χ [0,1] (s) + p 3 (s)χ [1,2] (s) , a.e. s ∈ [0, 2], dp 3 ds (s) = 0 .…”
Section: Examplesmentioning
confidence: 99%