1973
DOI: 10.1007/3-540-06054-5_12
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Mittelwerte des Molekulargewichtes und anderer Eigenschaften

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Cited by 76 publications
(7 citation statements)
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“…Ref. 22): a, -1 E = (2a, -1)/3 (11) It is clear that this relation does not hold in the present case, for E from Eq. (10) equals 0.13 and E from the viscosity exponent (Table 111) equals 0.24.…”
Section: Light-scatteringmentioning
confidence: 67%
See 1 more Smart Citation
“…Ref. 22): a, -1 E = (2a, -1)/3 (11) It is clear that this relation does not hold in the present case, for E from Eq. (10) equals 0.13 and E from the viscosity exponent (Table 111) equals 0.24.…”
Section: Light-scatteringmentioning
confidence: 67%
“…Bloomfield and Zimm37 extended the calculation for values of E > 0.2; for 6 = 0.24, + ( E ) = 1.4 X For the z-average radius of gyration, Eq. (22) becomes in which qzn is the polydispersity correction factor, which for a Schulz-Zimm distribution is given by22…”
Section: Application Of the Ptitsyn And Eizner Theorymentioning
confidence: 99%
“…For colligative methods, one gets4 = w.w3. (A)1 (2) and for weight average methods (light scattering, equilibrium ultracentrifugation) 46 = (…”
Section: (1)mentioning
confidence: 99%
“…When dealing with polydisperse samples, the experimental intrinsic viscosity of each sample is a weight av-erage of the intrinsic viscosities of the monomolecular species present in it. 21 However, the same Mark-Houwink equation valid for the monomolecular species holds with the M(exptl) of the polydisperse samples if their viscosity-average molecular weights, Mv, are used in eq 3 in place of M, namely log = log K + a log Mv (7) (K and a having the same values as in eq 3). The product M-Mv for polydisperse samples is then log (MMV) = log K + (1 + a) log Mv (8) If in eq 2 we use an average molecular weight, M, in place of M, we obtain a corresponding average elution volume, V (using the same coefficients A0lA1; ..., determined for monomolecular species).…”
Section: Resultsmentioning
confidence: 99%