2005
DOI: 10.1109/jssc.2005.843591
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Minimum achievable phase noise of RC oscillators

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Cited by 112 publications
(111 citation statements)
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“…In order to simplify (9), we first take note of the fact that, according to the fluctuation-dissipation theorem of thermodynamic, during the equilibrium time , the noise PSD in the NMOS and PMOS devices are given by and , respectively. If we further assume that the current flow in NMOS and PMOS transistors are nearly equal and equal to ( through proper device sizing), (9) can be simplified to (11) which after solving for gives (12) In order to find the total noise PSD we use (12) along with the value of from simulation results (Spice models at Typical corner) and the values of and from the measurements. For a supply voltage of 1.8 V , in this 0.18 CMOS process, total drain current noise PSD (NMOS+PMOS) is , , and at 0.18 , 0.38 , and 0.54 channel length, respectively.…”
Section: B Measurement Results and Discussionmentioning
confidence: 99%
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“…In order to simplify (9), we first take note of the fact that, according to the fluctuation-dissipation theorem of thermodynamic, during the equilibrium time , the noise PSD in the NMOS and PMOS devices are given by and , respectively. If we further assume that the current flow in NMOS and PMOS transistors are nearly equal and equal to ( through proper device sizing), (9) can be simplified to (11) which after solving for gives (12) In order to find the total noise PSD we use (12) along with the value of from simulation results (Spice models at Typical corner) and the values of and from the measurements. For a supply voltage of 1.8 V , in this 0.18 CMOS process, total drain current noise PSD (NMOS+PMOS) is , , and at 0.18 , 0.38 , and 0.54 channel length, respectively.…”
Section: B Measurement Results and Discussionmentioning
confidence: 99%
“…To calculate phase noise, we use the approach presented in [11]: first we calculate jitter in the time domain and then convert that to the frequency domain to find phase noise. To calculate jitter, we first calculate the variance of each switching instance.…”
Section: B Analytical Formulation Of Phase Noisementioning
confidence: 99%
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“…Such relaxation oscillators have two advantages with respect to ring oscillators: 1) they have a constant frequency tuning gain; and 2) their phase can be read out continuously due to their triangular (or sawtooth) waveform. A major disadvantage of practical relaxation oscillators is their poor phase-noise compared to ring oscillators [1,2,4].The 1/f 2 phase-noise performance of oscillators can be compared using the FoM definition given in Fig. 19.5.3 [1].…”
mentioning
confidence: 99%