“…, 7, 2,G k (α) = G 2 k (α + ) − G 2 k (α − ), k = 1, 2, 3, and G 2 1 (x) = x − 1 − 1 2x 2 − ln x, G 2 2 (x) = x −1 − x + 2 · ln x, G 2 3 (x) = 1 2 x −2 − 2x −1 + 3 2 − ln x. For j = 2 rearrangement of integrals yields J 2 + J 3 = K 2 (α) − K 3 (α), with Dehgani et al (2013), Rosco and Joe (2013), and Genest and Nešlehová (2014).…”