1934
DOI: 10.1021/ie50299a012
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Mass Transfer (Absorption) Coefficients Prediction from Data on Heat Transfer and Fluid Friction

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Cited by 961 publications
(283 citation statements)
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“…where h GL is the gas-liquid heat transfer coefficient in kJ/m 2 s, ∆H rxn is the heat of reaction between MEA and CO 2 in kJ/m 3 s and ∆H vap is the heat of vaporization of H 2 O in kJ/m 3 s. The gas-liquid heat transfer coefficient was determined using the Chilton-Colburn analogy [25].…”
Section: Heat and Mass Transfer Ratesmentioning
confidence: 99%
“…where h GL is the gas-liquid heat transfer coefficient in kJ/m 2 s, ∆H rxn is the heat of reaction between MEA and CO 2 in kJ/m 3 s and ∆H vap is the heat of vaporization of H 2 O in kJ/m 3 s. The gas-liquid heat transfer coefficient was determined using the Chilton-Colburn analogy [25].…”
Section: Heat and Mass Transfer Ratesmentioning
confidence: 99%
“…3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 and =1/3 (also for Re>40000). The theoretical study for a turbulent boundary layer using the Chilton-Colburn analogy [54], following the approach of Eckert and Jackson (1951) [55], gives =0.8 and =1/3. The fit of experimental data for mass transfer coefficients establishes that for 8000 < Re < 32000 =0.567 while =0.746 for 32000 < Perry's Handbook gives [46] values for (0.65, 0.70) (using Rousseau as reference [56]) and α=0.785 citing Blatt [57].…”
Section: Reynolds Numbermentioning
confidence: 99%
“…For turbulent flow, Reynold's number >5000: the average heat transfer coefficient was calculated using the Chilton-Colburn analogy [23] with the Churchill friction factor [24]. The pressure drop was calculated using Zigrang and Sylvester [25].…”
Section: Control Volume Definition and Governing Equationmentioning
confidence: 99%