2017
DOI: 10.1515/ms-2017-0019
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M-Cantorvals of Ferens type

Abstract: A special family of multigeometric series is considered from the point of view of behaviour of their sets of subsums. A sufficient condition for their sets of subsums to be M-Cantorvals is proven. The Lebesgue measure of those special M-Cantorvals is computed and it is shown to be equal to the sum of lengths of all component intervals of the M-Cantorvals. A new sufficient condition for the set of subsums of a series to be a Cantor set is formulated and it is used to demonstrate that the discussed multigeometri… Show more

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Cited by 8 publications
(6 citation statements)
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“…Obviously, for n greater then some n 0 2 n−1 s > n and hence 2 n−1 s n > n s n−1 which proves (2). , then there is a decreasing sequence (q n ) ∞ n=1 tending to 1 |Σ| such that, for any n ∈ N, the self-similar set K(Σ, q n ) has Lebesgue measure zero.…”
Section: Proof Clearlymentioning
confidence: 69%
See 1 more Smart Citation
“…Obviously, for n greater then some n 0 2 n−1 s > n and hence 2 n−1 s n > n s n−1 which proves (2). , then there is a decreasing sequence (q n ) ∞ n=1 tending to 1 |Σ| such that, for any n ∈ N, the self-similar set K(Σ, q n ) has Lebesgue measure zero.…”
Section: Proof Clearlymentioning
confidence: 69%
“…with m ≥ k we will call, after [2], Ferens-like sequences. The achievement set E (x) for a Ferens-like sequence coincides with the self-similar set K(Σ; q) for the set…”
Section: Sets Of Positive Measurementioning
confidence: 99%
“…Such Cantorvals do exist. For example, it suffices to take the Ferens type series F (2, 5; 1 16 ) (see [2,Lemma 7]). Since the set n C(F n ) is countable for any series a n , the equality C(E) = n C(F n ) does not hold for any series satisfying the assumptions of the Fact 2.6.…”
Section: Fact 23 Given a Convergent Seriesmentioning
confidence: 99%
“…A series a n is said to be fast convergent if a n > r n for all n. Fast convergence of a n is a sufficient condition for E to be a Cantor set ( [13], [14], [20]). Some other sufficient conditions for E to be a Cantor set can be found in [1], [2] and [7].…”
mentioning
confidence: 99%
“…Recently, there have appeared a lot of interesting papers that explore properties of achievement sets, i.a. [5], [7], [27], [9], and [6].…”
Section: Introductionmentioning
confidence: 99%