2014
DOI: 10.1134/s156035471403006x
|View full text |Cite
|
Sign up to set email alerts
|

Lyapunov orbits in the n-vortex problem

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
7
0

Year Published

2015
2015
2021
2021

Publication Types

Select...
6
1

Relationship

1
6

Authors

Journals

citations
Cited by 8 publications
(7 citation statements)
references
References 27 publications
0
7
0
Order By: Relevance
“…Bifurcation from the equilateral triangle: Recall that the minimum of H CP n-2 is achieved when the 4 vortices form the centred square (4-polygon). Thus the Moser-Weinstein theorem should show the existence of relative periodic solutions of short period, bifurcating from the square [6,7,5];…”
Section: Comparison With Other Methodsmentioning
confidence: 99%
See 1 more Smart Citation
“…Bifurcation from the equilateral triangle: Recall that the minimum of H CP n-2 is achieved when the 4 vortices form the centred square (4-polygon). Thus the Moser-Weinstein theorem should show the existence of relative periodic solutions of short period, bifurcating from the square [6,7,5];…”
Section: Comparison With Other Methodsmentioning
confidence: 99%
“…For example methods based on the Lyapunov centre theorem around relative equilibria, or based on superposition principles (i.e. substituting a number of bodies in small relative equilibrium configuration for another body) have been applied successfully to find non-equilibrium periodic solutions in the n-vortex problem from Euler equation [5,7,3,4]. Even some particular qualitative properties (for instance some discrete symmetry of these orbits) could be deduced for these solutions.…”
Section: Absolute and Relative Periodic Orbitsmentioning
confidence: 99%
“…Due to rotational invariance there is always a zero frequency, ν 0 = 0. Since the frequencies have 1 : 1 resonances (ν k = ν n−k ), straightforward application of the Lyapunov center theorem is not possible, except for some cases with k = n/2 for n = 2, 4, 6, see [12]. For example, for n = 6 we have…”
Section: The N-polygon Of Vortices In the Planementioning
confidence: 99%
“…We will call such a relative equilibrium a ring of vortices. The planar case of a ring of vortices with and without a central vortex as well as the case of a ring of vortices on the sphere without a vortex at north pole were treated in the paper [10].…”
Section: Introductionmentioning
confidence: 99%