2011
DOI: 10.1002/jgt.20616
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Long cycles in subgraphs of (pseudo)random directed graphs

Abstract: We study the resilience of random and pseudorandom directed graphs with respect to the property of having long directed cycles. For every 0 < γ < 1/2 we find a constant c = c(γ) such that the following holds. Let G = (V, E) be a (pseudo)random directed graph on n vertices, and let G ′ be a subgraph of G with (1/2 + γ)|E| edges. Then G ′ contains a directed cycle of length at least (c − o(1))n. Moreover, there is a subgraph G ′′ of G with (1/2 + γ − o(1))|E| edges that does not contain a cycle of length at leas… Show more

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Cited by 24 publications
(29 citation statements)
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“…By taking the union bound over all n ≤ (1+ε)k vertices, we can deduce (a). For (b), let A be a set of size t ≤ n (log k) 3/2 and let B be a set of size ε 3 t log k. If e Gp (A, B) ≥ ε 2 2 t log k and A and B are not disjoint, then let A = A \ B, B = B \ A, and add the vertices in A ∩ B, independently and uniformly at random to A or B . By linearity of expectation, we have…”
Section: For Every Subsetmentioning
confidence: 99%
See 1 more Smart Citation
“…By taking the union bound over all n ≤ (1+ε)k vertices, we can deduce (a). For (b), let A be a set of size t ≤ n (log k) 3/2 and let B be a set of size ε 3 t log k. If e Gp (A, B) ≥ ε 2 2 t log k and A and B are not disjoint, then let A = A \ B, B = B \ A, and add the vertices in A ∩ B, independently and uniformly at random to A or B . By linearity of expectation, we have…”
Section: For Every Subsetmentioning
confidence: 99%
“…The main technique we use in proving our theorems is a technique recently developed in Refs. and , based on the depth first search algorithm. In Section 2, we discuss this technique in detail and also provide some probabilistic tools that we will need later.…”
Section: Introductionmentioning
confidence: 99%
“…The following lemma is due to Ben‐Eliezer, Krivelevich, and Sudakov and is a useful application of the Depth‐first search (DFS) algorithm.Lemma Given an oriented graph G, there is a directed path P such that vertices of G – P can be partitioned into two disjoint sets U and W such that |U|=|W| and all the edges between U and W are oriented from W to U.Proof We start with U=, W=V(G) and P=. We repeat the following procedure, throughout of which P is a path, |W||U| and all edges between U and W are oriented from W to U . If P is empty we take any vertex from W to be the new path P and remove the vertex from W .…”
Section: Preliminariesmentioning
confidence: 99%
“…The following lemma, based on the Depth-first-search (DFS) algorithm, is an easy generalisation, for trees, of the version for paths introduced by Ben-Eliezer, Krivelevich and Sudakov [3,4]; it will be very useful in several parts of this section.…”
Section: Preliminariesmentioning
confidence: 99%