2010
DOI: 10.1103/physrevb.81.205432
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Logarithmic scaling of Lyapunov exponents in disordered chiral two-dimensional lattices

Abstract: We analyze the scaling behavior of the two smallest Lyapunov exponents for electrons propagating on two-dimensional lattices with energies within a very narrow interval around the chiral critical point at E = 0 in the presence of a perpendicular random magnetic flux. By a numerical analysis of the energy and size dependence we confirm that the two smallest Lyapunov exponents are functions of a single parameter. The latter is given by ln L/ ln ξ(E), which is the ratio of the logarithm of the system width L to t… Show more

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Cited by 10 publications
(12 citation statements)
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References 30 publications
(57 reference statements)
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“…where p/q (p and q are mutually prime integers) is the rational number of magnetic flux quanta h/e per plaquette 2a 2 , and B = ph/(2qea 2 ) is the magnetic flux density perpendicular to the two-dimensional lattice. This differs from the random flux model of our previous work 25 , where the constant magnetic field part was absent. The random part originates from the magnetic fluxes φ x,y , which are uniformly distributed −f /2 ≤ φ x,y ≤ f /2 with zero mean and disorder strength 0 ≤ f /(h/e) ≤ 1.…”
Section: Modelscontrasting
confidence: 83%
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“…where p/q (p and q are mutually prime integers) is the rational number of magnetic flux quanta h/e per plaquette 2a 2 , and B = ph/(2qea 2 ) is the magnetic flux density perpendicular to the two-dimensional lattice. This differs from the random flux model of our previous work 25 , where the constant magnetic field part was absent. The random part originates from the magnetic fluxes φ x,y , which are uniformly distributed −f /2 ≤ φ x,y ≤ f /2 with zero mean and disorder strength 0 ≤ f /(h/e) ≤ 1.…”
Section: Modelscontrasting
confidence: 83%
“…The same exponent was found also for a similar model defined on the square lattice. 25 This result confirms theoretical predictions that for |E| ≪ E 0 the localization length is ξ(E) = ξ 0 exp[A(ln(E 0 /|E|)) κ ] with a universal exponent κ = 1/2. 15,21 However, the recent suggestion 24 that nonperturbative effects have to be taken into account applies also to these investigations.…”
Section: Introductionsupporting
confidence: 88%
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