“…The proof follows from Lemma 2.1, and the fact that Q p ðÊ þ Þ ¼Ê þ , and likewise, as an operator, Q p ðintðÊ þ ÞÞ ¼ intðÊ þ Þ, becauseÊ þ is a symmetric cone [15]. h Now, with this change of variables, Problem (6) and (7) becomes min e gðl; xÞ :¼ 1 Observe that Problems (7) and (12) have the same minimizer but their optimal objective values are equal up to the constant 2l ln det p (as detðQ p qÞ ¼ det 2 ðpÞ detðqÞ for any two elements p; q 2 E m [16, Chapters II]).…”