Elementary Linear Algebra 2016
DOI: 10.1016/b978-0-12-800853-9.00005-0
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Linear Transformations

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Cited by 3 publications
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“…Such differences in the growth rate appear to be due the differences in the function and functional requirement of each body dimension [13][14][15][16][17]. Biplot demonstration showed that the wing component of female Bali duck such as radius ulna, tarsal and humerus have slower growth rates as compared to the leg components which are required to be functional earlier such as digital 2, 3 and 4.…”
Section: Resultsmentioning
confidence: 99%
“…Such differences in the growth rate appear to be due the differences in the function and functional requirement of each body dimension [13][14][15][16][17]. Biplot demonstration showed that the wing component of female Bali duck such as radius ulna, tarsal and humerus have slower growth rates as compared to the leg components which are required to be functional earlier such as digital 2, 3 and 4.…”
Section: Resultsmentioning
confidence: 99%
“…To overcome server consolidation problem, the algorithm computes a minimum number of block www.ijacsa.thesai.org mr (Line-10), which are obtained from v1 and v2 that corresponds to the sum of all stationary distribution from 1 to (k-1) and 1 to k respectively. The stationary distribution is obtained by applying row reduction method [30]. Minimum resource block is then computed considering the input parameters of i) k (all numbers of VMs allowed on physical servers), ii) switching state S 1 from OFF state to ON state, iii) switching state S 2 from ON state to OFF state, and minimum resource mr (Line-12) that is finally sorted to obtain the better resource block (Line-14).…”
Section: Endmentioning
confidence: 99%