2018 IEEE International Symposium on Information Theory (ISIT) 2018
DOI: 10.1109/isit.2018.8437805
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Lifting Private Information Retrieval from Two to any Number of Messages

Abstract: We study private information retrieval (PIR) on coded data with possibly colluding servers. Devising PIR schemes with optimal download rate in the case of collusion and coded data is still open in general. We provide a lifting operation that can transform what we call one-shot PIR schemes for two messages into schemes for any number of messages. We apply this lifting operation on existing PIR schemes and describe two immediate implications. First, we obtain novel PIR schemes with improved download rate in the … Show more

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Cited by 13 publications
(14 citation statements)
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“…The main contribution of this paper is the proof for the capacity of MDS-coded, linear, symbol-separated PIR with coded and colluding servers. The converse (upper bound) is given by Theorem 1, and an achievable scheme can be found by combining [12] and [15,Thm. 3], where a lift operation is introduced, which together with the star product scheme [12] achieves the derived capacity upper bound.…”
Section: Introductionmentioning
confidence: 99%
“…The main contribution of this paper is the proof for the capacity of MDS-coded, linear, symbol-separated PIR with coded and colluding servers. The converse (upper bound) is given by Theorem 1, and an achievable scheme can be found by combining [12] and [15,Thm. 3], where a lift operation is introduced, which together with the star product scheme [12] achieves the derived capacity upper bound.…”
Section: Introductionmentioning
confidence: 99%
“…Note that the curve for the systematic scheme follows a staircase in which there arek points on each horizontal line of the staircase. This follows directly from the term ñ k in the definition ofn in (29).…”
Section: Numerical Resultsmentioning
confidence: 95%
“…Assume that n −k ≤ k. Then, 1 ≤ ñ k ≤ 1 + k k ≤ 2. If ñ k = 1, then it follows directly from (29) and Lemma 6 that n =n and ν = k + n −k = k + min{k, n −k}. Otherwise, if ñ k = 2, then k =k, 3k > n ≥ 2k, and from (29), we haven = k +k = 2k.…”
Section: Recovery and Privacymentioning
confidence: 96%
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