2012
DOI: 10.1016/j.topol.2012.03.011
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Lefschetz periodic point free self-maps of compact manifolds

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Cited by 6 publications
(6 citation statements)
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“…Remark 11. A map f is called Lefschetz periodic point free if L(f m ) = 0, for all m ∈ N. In [8], it is claimed that there are no Lefschetz periodic point free maps on CP n and HP n , that is, all self-maps of CP n and HP n have periodic points. Here, we see that in particular Morse-Smale diffeomorphisms in CP n and HP n always have fixed points, unless when n is odd and d = −1, where in this case, there are always fixed points or periodic points of period 2.…”
Section: Periods Of Morse-smale Diffeomorphisms On Cp N and Hp Nmentioning
confidence: 99%
See 1 more Smart Citation
“…Remark 11. A map f is called Lefschetz periodic point free if L(f m ) = 0, for all m ∈ N. In [8], it is claimed that there are no Lefschetz periodic point free maps on CP n and HP n , that is, all self-maps of CP n and HP n have periodic points. Here, we see that in particular Morse-Smale diffeomorphisms in CP n and HP n always have fixed points, unless when n is odd and d = −1, where in this case, there are always fixed points or periodic points of period 2.…”
Section: Periods Of Morse-smale Diffeomorphisms On Cp N and Hp Nmentioning
confidence: 99%
“…In [8], the authors study the Lefschetz periodic point free self-maps on S m × S n , CP n and HP n . Our results give extended information in the same line for the Morse-Smale diffeomorphisms.…”
Section: Introductionmentioning
confidence: 99%
“…Note that if f is periodic point free, then f is Lefschetz periodic point free, but in general the converse does not hold. Periodic point free and Lefschetz periodic point free maps have been studied previously, see for instance [5,6,12,13].…”
Section: Introduction and Statement Of The Main Resultsmentioning
confidence: 99%
“…Let f : X → X be a continuous self-map on X, its Lefschetz zeta function has the form: (5) ζ f (t) = (1 − t) −1 q 1 (t) (−1) n 1 +1 • • • q l (t) (−1) n l +1 , where q k (t) = det(Id * n k − tf * n k ), clearly it is a polynomial of degree smaller than or equal to s k , the degree is s k if and only if 0 is not an eigenvalue of f * n k . So if p k (t) is the characteristic polynomial of f * k , we have p k (t) = (−1) s k t s k q k (1/t).…”
Section: Proof Of Theoremmentioning
confidence: 99%
“…Using the fact that α 2 = β 2 = 0 and well-known properties of cohomology ring, cf. [14] for details, we obtain * 4…”
Section: Case (I)mentioning
confidence: 99%