2006
DOI: 10.1017/s0024611506015930
|View full text |Cite
|
Sign up to set email alerts
|

Kazhdan–lusztig Cells and the Murphy Basis

Abstract: Abstract. Let H be the Iwahori-Hecke algebra associated with Sn, the symmetric group on n symbols. This algebra has two important bases: the Kazhdan-Lusztig basis and the Murphy basis. While the former admits a deep geometric interpretation, the latter leads to a purely combinatorial construction of the representations of H, including the Dipper-James theory of Specht modules. In this paper, we establish a precise connection between the two bases, allowing us to give, for the first time, purely algebraic proof… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1
1

Citation Types

1
74
0

Year Published

2007
2007
2022
2022

Publication Types

Select...
6
1

Relationship

2
5

Authors

Journals

citations
Cited by 43 publications
(75 citation statements)
references
References 17 publications
1
74
0
Order By: Relevance
“…Then, as already mentioned in Example 3.8, all the two-sided cells in W are smooth, and so we now recover a known result of Schützenberger [Sch] in this case. An elementary proof that Lusztig's P Conjectures for (W, S, ϕ) hold is given in [Ge3] (see also [GeJa,§2.8…”
Section: Bonnafé and M Geckmentioning
confidence: 99%
“…Then, as already mentioned in Example 3.8, all the two-sided cells in W are smooth, and so we now recover a known result of Schützenberger [Sch] in this case. An elementary proof that Lusztig's P Conjectures for (W, S, ϕ) hold is given in [Ge3] (see also [GeJa,§2.8…”
Section: Bonnafé and M Geckmentioning
confidence: 99%
“…Then, {(7, 5, 3, 1), (8,6, 2), (9, 4)} and { (7,5,3,2), (9, 6, 1), (8,4)} are decreasing covers of type (4,3,2) for w, the first being a symmetric decreasing cover. Also, { (7,8,9), (1,2,4), (3,6), (5)} is an increasing cover of type (3, 3, 2, 1) for w.…”
Section: Coversmentioning
confidence: 99%
“…In particular, if ν has parts of the same size, it is possible to find distinct elements e and e with (ν, e) and (ν, e ) corresponding to P. , 5, 7, 3, 6, 4] and P = {(7, 6, 4), (2, 1), (5, 3)}. We may take e = [4, 6, 7, 1, 2, 3, 5] and e = [4,6,7,3,5,1,2]. Then e, e ∈ X J(ν) and P = P ν e = P ν e .…”
Section: Coversmentioning
confidence: 99%
See 2 more Smart Citations