“…where b = (h 0 − h 1 )/2, γ i = −2c(c/λ + (−1) i h i ), i = 0, 1, see formula (4.2) in [22]. In particular, if in this symmetric case the jumps are also symmetric, h 0 = −h 1 = h, and X is the martingale, c + λ h = 0, then B = 0, c + λ b = 0 and γ 0 = γ 1 = 0.…”