2016
DOI: 10.1016/j.hm.2016.03.001
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Jost Bürgi's method for calculating sines

Abstract: From various sources we know that the Swiss instrument maker and mathematician Jost Bürgi (1552-1632) found a new way of calculating any sine value. Many mathematicians and historians of mathematics have tried to reconstruct his so-called "Kunstweg" ("skillful / artful method"), but they did not succeed. Now a manuscript by Bürgi himself has been found which enables us to understand his procedure. The main purpose of this article is to explain Bürgi's method. It is totally different from the conventional way t… Show more

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Cited by 7 publications
(15 citation statements)
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“…As mentioned above, the convergence of the original Bürgi algorithm was already proven in [9,30]. The other assertions of Theorem 1 are new.…”
Section: Figure 1 Jost Bürgi (Eth Library Zurich)mentioning
confidence: 72%
See 3 more Smart Citations
“…As mentioned above, the convergence of the original Bürgi algorithm was already proven in [9,30]. The other assertions of Theorem 1 are new.…”
Section: Figure 1 Jost Bürgi (Eth Library Zurich)mentioning
confidence: 72%
“…After consulting the hand-written catalog of the manuscripts' collection, he ordered microfilms of several works (personal communication). Folkerts looked as late as 2013 to one of those microfilms and recognized that the autograph Fundamentum Astronomiae [2], written in German by Jost Bürgi, contained the author's lost algorithm for computing sine tables (Figures 2 and 3) [8,9] Bürgi's example of his skillful method, the Artificium, explains the calculation for the multiples of 10 • , the ninth parts of the right angle. If we leave away zeros and column shifts in Figure 3, write sexagesimal numbers in base ten (for example 1 ′′ 3 ′′′ = 1 × 60 + 3 = 63 at the top of the next to rightmost column), and rotate the table by a quarter-turn, we obtain HOW BÜRGI COMPUTED THE SINES OF ALL INTEGER ANGLES SIMULTANEOUSLY IN 1586 3 the following first three lines from the three rightmost columns Sinus 1 to Sinus 2:…”
Section: Figure 1 Jost Bürgi (Eth Library Zurich)mentioning
confidence: 99%
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“…In [1] Andreas Thom has proven that Bürgis claim is true: The step from the vector (a (k) j ) 1≤j≤N to the vector (a (k+1) j ) 1≤j≤N is given by multiplication with a matrix with only positive entries. Therefore, by the Perron-Frobenius theorem of 1907/12, it has a dominant eigenvalue, to which corresponds the eigenvector (sin ∆, sin 2∆, .…”
Section: Proofs Using Modern Meansmentioning
confidence: 99%