“…The unique combination of ωg that yielded the lowest β 2 is 60 as shown in Table 2. This obtained unique combination is saved in set V. Now V = 1, therefore, the optimum combination ω 0 = ωg = 4, 6,7,9,11,12,13,15,17,19,20,21,22,23,24, 26 corresponds to minimum β 2 , i.e. 60, is selected and algorithm-2 is terminated at this stage.…”