2008
DOI: 10.2140/ant.2008.2.31
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Joint moments of derivatives of characteristic polynomials

Abstract: We present a simple technique to compute moments of derivatives of unitary characteristic polynomials. The first part of the technique relies on an idea of Bump and Gamburd: it uses orthonormality of Schur functions over unitary groups to compute matrix averages of characteristic polynomials. In order to consider derivatives of those polynomials, we here need the added strength of the Generalized Binomial Theorem of Okounkov and Olshanski. This result is very natural as it provides coefficients for the Taylor … Show more

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Cited by 25 publications
(71 citation statements)
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References 33 publications
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“…where Φ ∞ (z), Φ 0 (z), and Φ 1 (z) are holomorphic and invertible in neighbourhoods of the respective points. Also, (3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14)(15)(16) we see that, in our case, the formal monodromy exponents θ ∞ , θ 0 , and θ 1 are…”
Section: Painlevé V and The Laguerre Determinantsupporting
confidence: 53%
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“…where Φ ∞ (z), Φ 0 (z), and Φ 1 (z) are holomorphic and invertible in neighbourhoods of the respective points. Also, (3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14)(15)(16) we see that, in our case, the formal monodromy exponents θ ∞ , θ 0 , and θ 1 are…”
Section: Painlevé V and The Laguerre Determinantsupporting
confidence: 53%
“…The results obtained suggest that in general F N (h, k) grows like N k 2 +2h as N → ∞ and it is a key problem to prove this and then to evaluate the limit (1)(2)(3)(4) F (h, k) := lim N →∞ 1 N k 2 +2h F N (h, k). For h, k ∈ N, k > h − 1/2, an expression for F N (h, k) was obtained in [12] in terms of certain sums over partitions. A similar answer was also found in the case h = (2m − 1)/2, m ∈ N, k ∈ N, k > h − 1/2 in [46] (see [46] also for a survey on other related results).…”
Section: Introductionmentioning
confidence: 99%
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“…I first saw the explicit formula (5) in a preprint of Dehaye [1] (who attributes it to Hughes). In the case h = 3 the formula as I have written it in (4) requires adjustment to fit with (5) in that an extra factor κ 2 − 9 should be introduced in both the numerator and denominator.…”
Section: The Parametersmentioning
confidence: 99%