J dependence in

T20Tanalyzing powers fromC12(

“…A spin-parity value of 11/2 − proposed earlier [13] for the state in 15 N at 13.00 MeV was confirmed by analyzing powers from the 12 C( 6 Li, 3 He) 15 N reaction at E lab ( 6 Li) = 50 MeV [14]. A reanalysis of just the unpolarized angular distribution data [12] confirmed that the spin-parity of this state could not be obtained from these data alone, which nicely showed the importance of analyzing powers for extracting final state J π values.…”

“…Kemper et al [14] proposed J π = 7/2 + or 5/2 − for a 13.17 MeV state based on an analysis of the polarized beam 12 C( 6 Li, 3 He) 15 N reaction at E( 6 Li) = 50 MeV. A more recent study of the same reaction by Lee et al [12] suggested a J π value of 5/2 − based on the analysis of unpolarized and polarized data.…”

Spin and parity determinations of excited 15N based on polarized and unpolarized 12C(7Li,α)15N reaction data at Elab=34MeV

“…Table 1 Woods-Saxon potential parameters used in the FRESCO calculations [7] for the 12 C( 7 Li, a) 15 N reaction at E lab = 34 MeV V 0 (MeV) r R (fm) a R (fm) W 0 (MeV) r I (fm) a I (fm) 7 Li + 12 C 145. 6 1 The 15 N state at 14.09 MeV has been reported in previous works [11] as 9/2 + or 7/2 + but, in a recent research [7], it is proposed to be 5/2 À . Fig.…”

“…Test calculations were carried out for the known 10.69 MeV (9/2 + ) state to determine if the analyzing power data collected were sufficiently distinctive to determine the 15 N spin and parity, as it was done in previous works [6,7]. As shown in Fig.…”

“…A previous study of the polarized 12 C( 6 Li,3 He) reaction at E( 6 Li) = 34 MeV showed that the measured vector analyzing powers are sensitive to the J p of the transferred cluster [6]. The angular distribution data obtained by Lee et al [7] from the 12 C( 6 Li,3 He) reaction at E lab ( 6 Li) = 50 MeV restricted the J p values of the 13.01 MeV state to 5/2 À , 7/ 2 À , 7/2 + and 11/2 À , while the combined angular distribution and vector analyzing power data were only consistent with a 11/2 À assignment.…”