2022
DOI: 10.1016/j.ejcon.2022.100665
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ISS inequalities for vector versions of Halanay’s inequality and of the trajectory-based approach

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Cited by 3 publications
(5 citation statements)
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“…A second possible line of research is the use of vector versions of Halanay conditions. It was shown in References 33–35 that matrix‐based conditions can be derived to conclude stability of systems involving several Lyapunov functions, which turns out particularly useful for networks of interconnected dynamical systems. While the techniques presented here allow for the construction of an LKF in that setup, the conditions we obtained so far appear too demanding as compared to the flexibility offered the original vector extension of Halanay's inequality.…”
Section: Discussionmentioning
confidence: 99%
“…A second possible line of research is the use of vector versions of Halanay conditions. It was shown in References 33–35 that matrix‐based conditions can be derived to conclude stability of systems involving several Lyapunov functions, which turns out particularly useful for networks of interconnected dynamical systems. While the techniques presented here allow for the construction of an LKF in that setup, the conditions we obtained so far appear too demanding as compared to the flexibility offered the original vector extension of Halanay's inequality.…”
Section: Discussionmentioning
confidence: 99%
“…In the second part, we use the bound on |x(t) − x(t i )| from the first part to find a vector valued upper bound on ṡ(t) where s(t) = x(t) − x(t) is the difference between upper and lower vectors in an interval observer (x, x) for x. In the final part, we use the bound on ṡ(t) from the second part and a variant of the ISS vector Halanay's inequality from [6] to obtain our ISS estimate (8).…”
Section: B Proof Of Theoremmentioning
confidence: 99%
“…We apply [6, Theorem 1] to the function w(t) = s(t) and τ = 2(T + ∆ ♯ ), after extending s to the domain [−τ, +∞) by defining s to be constant on [−τ, 0], so we use a piecewise C 1 function w instead of assuming that w is C 1 as was assumed in [6]; this is valid because the proof of [6, Theorem 1] remains valid if the C 1 requirement on w in [6] is relaxed to only requiring it to be piecewise C 1 . This ensures that s satisfies an ISS property when…”
Section: B Proof Of Theoremmentioning
confidence: 99%
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