2018
DOI: 10.4310/jsg.2018.v16.n4.a3
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Invariants of Legendrian and transverse knots in monopole knot homology

Abstract: We use the contact invariant defined in [2] to construct a new invariant of Legendrian knots in Kronheimer and Mrowka's monopole knot homology theory (KHM ), following a prescription of Stipsicz and Vértesi. Our Legendrian invariant improves upon an earlier Legendrian invariant in KHM defined by the second author in several important respects. Most notably, ours is preserved by negative stabilization. This fact enables us to define a transverse knot invariant in KHM via Legendrian approximation. It also makes … Show more

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Cited by 19 publications
(23 citation statements)
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“…The second author and Rutherford [35,Theorem 5.4] showed that if the ruling polynomial R Λ (z) has positive degree then Λ is A (2) -compatible. 1 The following result is similar but allows for R Λ (z) to be a constant as well.…”
Section: A (2)mentioning
confidence: 87%
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“…The second author and Rutherford [35,Theorem 5.4] showed that if the ruling polynomial R Λ (z) has positive degree then Λ is A (2) -compatible. 1 The following result is similar but allows for R Λ (z) to be a constant as well.…”
Section: A (2)mentioning
confidence: 87%
“…There are infinitely many Legendrian knots Λ such that U ≺ Λ but Λ ≺ U . 1 The convention in [35] is that a ruling ρ with s switches and c right cusps contributes z s−c to the ruling polynomial, so their condition is deg RΛ(z) ≥ 0. We instead use the convention z s−c+1 of [40], so that the 2-graded and ungraded ruling polynomials match the appropriate coefficients of the HOMFLY-PT and Kauffman polynomials respectively.…”
Section: A (2)mentioning
confidence: 99%
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“…Given the existence of exact, non-orientable Lagrangian endocobordisms for a stabilized Legendrian, it is natural to ask: What Legendrian knots can appear as a "slice" of such an endocobordism? The parallel question for orientable Lagrangian endocobordisms has been studied in [9,4,12]. The non-orientable version of this question is closely tied to the question of whether non-orientable Lagrangian cobordisms define an equivalence relation on the set of Legendrian knots.…”
Section: Introductionmentioning
confidence: 99%