“…According to Theorem 4.14, St((H 1 ∩ H 2 )π, {w 1 , w 2 }) Cay(Z/Z ⊕ Z/0Z, {(1, 0), (0, 1)}) Cay(Z, {0, 1}), which takes the form: Since Z is infinite, in Case 2 the intersection H 1 ∩ H 2 has infinite rank. After replacing the arcs reading w 1 and w 2 with the enriched paths reading x 6 t (6,6), (6,6) and yx 3 y −1 t (3,3),(0,0) , folding, and normalizing (w.r.t. the spanning tree having as cyclomatic arcs the thicker ones), and equalizing, we obtain a Stallings automaton for H 1 ∩ H 2 : The corresponding (infinite) basis for H 1 ∩ H 2 is {yx 3k y −1 x 6 yx −3k y −1 t (6,6) : k ∈ Z}.…”