“…Assuming that the data bit error and the amplitude estimation error are independent, the introduced interference variance can be calculated as (12) Combining the above cases, the average interference variance contribution from one bit of user conditioned on its amplitude is (13) If the received user signals have unequal powers, we may assume that the received amplitudes are uniformly distributed between and , where is the amplitude of the weakest user and is the ratio of . The average interference variance contribution from user can be calculated by averaging (13) over the distribution of , which is assumed uniform in [ ]. Denote the expectation (14) and by using the approximation (15) Substituting (14) and (15) into (13), the total interference for all users including the channel noise variance is the solution to (16) For example, for an amplitude averaging length of bits, signal-to-noise ratio (SNR) of 10 dB, near-far ratio of 10 dB, spreading factor of , and number of users , the loss to the single-user bound is about 0.35 dB for threshold , 0.68 dB for , and 1.93 dB for .…”