2012
DOI: 10.1016/j.ress.2012.02.001
|View full text |Cite
|
Sign up to set email alerts
|

Integrating production, inventory and maintenance planning for a parallel system with dependent components

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1
1
1

Citation Types

0
34
0

Year Published

2014
2014
2021
2021

Publication Types

Select...
4
4

Relationship

0
8

Authors

Journals

citations
Cited by 82 publications
(34 citation statements)
references
References 26 publications
0
34
0
Order By: Relevance
“…Najid et al [25] extended the model in [24] to include demand time windows and shortage cost. Nourelfath and Chatelet [26] discussed the same planning problem for a production system composed of a set of parallel components, in the presence of economic dependence and common cause failures. Zhao et al [27] assume order-dependent-failure (ODF) and proposed an iterative method to solve the problem on a single-machine system.…”
Section: A Brief Review Of the Literaturementioning
confidence: 99%
“…Najid et al [25] extended the model in [24] to include demand time windows and shortage cost. Nourelfath and Chatelet [26] discussed the same planning problem for a production system composed of a set of parallel components, in the presence of economic dependence and common cause failures. Zhao et al [27] assume order-dependent-failure (ODF) and proposed an iterative method to solve the problem on a single-machine system.…”
Section: A Brief Review Of the Literaturementioning
confidence: 99%
“…Nourelfath et al [15] also developed an integrated model for production and PM planning in multi-stage systems, where the preventive maintenance selection task in the integrated planning model is solved using a genetic algorithm. This work was then extended by Nourelfath and Chatelet [14] to a parallel system with dependent components, and a simulated annealing algorithm was developed. These works were well studied about the integrated problem, but some assumptions can be relaxed.…”
Section: Assumptionsmentioning
confidence: 99%
“…Since the probability for inspection renewal is 1 À P(X \ T) n , the expected renewal cycle length of this scenario is For any t 2 (0, T), the probability that the system has failed The expected renewal cycle length is the sum of equations (14) and (15), denoted by E(L 2 ), and is given by The expected cost per unit time is given by…”
Section: The Special Casementioning
confidence: 99%