Influence of quantum turbulence on the evolution of moderate plane second sound heat pulses in helium II

Study of the transient thermal wave heat transfer in a channel immersed in a bath of superfluid helium

“…Shown in Fig. 5(b) and (c) are the calculated results and the experimental ones cited from [24]. As can be seen from the figure, the present calculated results and experimental ones agree quite well with each other.…”

“…6, the present calculated results agree rather well with the experimental ones and show the improvement to the calculated results in Ref. [24]. As the distance of the fixed points from the heater surface increases, the range of the temperature overshoot becomes wider and the amplitude of it also decreases.…”

“…The comparison of the temperature histories at different fixed distances above the heater surface to the experimental and theoretical results cited from [24]. (a) The present calculated results, (b) the calculated results cited from [24], (c) the experimental results cited from [24]. t R = 0.5 s. The initial VLD = 1 · 10 6 cm À2 is the same as that used in [24].…”

“…Nemirovskii and Fiszdon [22] intensively reviewed the development of equations for the description of the hydrodynamic process in He II. To solve these equations, Kondaurova et al [23] and Fiszdon and Schwerdtner [24] expanded all the hydrodynamic equations into a power series and analyzed numerically to investigate the propagation of the thermal wave in the unperturbed He II bath. In their analysis, the absence of the mass transfer was generally assumed, which directly led to qv = 0.…”

“…[24], a parameter t R is used to refer the repetition time of the release of the thermal wave. It is believed that when t R is small, the background level of VLD is generally higher because the frequent release of the thermal wave in He II will cause the VLD does not have enough time to recover to the previous level, thus the next evolution of VLD will start from a relatively higher level; and vice versa, t R = 5 s. The initial VLD of is 1 · 10 6 cm À2 , the same as that used in [24].…”