2015
DOI: 10.1002/mana.201400355
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Induced Riemannian structures on null hypersurfaces

Abstract: Given a null hypersurface $L$ of a Lorentzian manifold, we construct a Riemannian metric $\widetilde{g}$ on it from a fixed transverse vector field $\zeta$. We study the relationship between the ambient Lorentzian manifold, the Riemannian manifold $(L,\widetilde{g})$ and the vector field $\zeta$. As an application, we prove some new results on null hypersurfaces, as well as known ones, using Riemannian techniques.Comment: 26 page

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Cited by 37 publications
(45 citation statements)
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“…It is known that a totally umbilic null hypersurface with a closed normalization splits locally as a twisted product, the decomposition being global if M is simply connected and the rigged vector field complete, [20,Theorem 5.3]. We show here that if moreover it admits a closed conformal rigging in an ambient space form, the local twisted product structure of the rigged metric is in fact a warped product.…”
Section: Completeness Of (M G)mentioning
confidence: 82%
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“…It is known that a totally umbilic null hypersurface with a closed normalization splits locally as a twisted product, the decomposition being global if M is simply connected and the rigged vector field complete, [20,Theorem 5.3]. We show here that if moreover it admits a closed conformal rigging in an ambient space form, the local twisted product structure of the rigged metric is in fact a warped product.…”
Section: Completeness Of (M G)mentioning
confidence: 82%
“…Proof. Using [20,Theorem 5.3], the only point we are going to show is the warped decomposition of (M, g).…”
Section: Completeness Of (M G)mentioning
confidence: 99%
See 1 more Smart Citation
“…Using (42) one has ∇ ∂ ∂u a ξ F = −x 0 ∇ ∂ ∂u a n − ∂x 0 ∂u a n = −x 0 ∇ ∂ ∂u a n + F u a x 0 ξ F . This latter together with (8) and (50) give Aξ= x 0 ∇ · n and τ = η.…”
Section: A Specialmentioning
confidence: 86%
“…For this reason, we are going to relate Ricci tensor of ∇ α with the one of ∇ for sections of T M . In [8], such a relationship was found for α = 1 and by assuming that M is totally geodesic. We are going to relate this Ricci tensor for a function α constant on the leaves of the screen distribution and without total geodesibility condition.…”
Section: Now Using Equation (11) This Becomesmentioning
confidence: 89%