2019
DOI: 10.1002/aenm.201901676
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In Situ Revealing the Electroactivity of PO and PC Bonds in Hard Carbon for High‐Capacity and Long‐Life Li/K‐Ion Batteries

Abstract: The low capacity and unsatisfactory rate capability of hard carbon still restricts its practical application for Li/K‐ion batteries. Herein, a low‐cost and large‐scale method is developed to fabricate phosphorus‐doped hard carbon (PHC‐700) by crosslinking phosphoric acid and epoxy resin and followed by annealing at 700 °C. H3PO4 acts not only as a crosslinker to solidify epoxy resin for promoting the degree of graphitization and lowering the specific surface area, but also as phosphorus source for forming PC … Show more

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Cited by 207 publications
(131 citation statements)
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“…According to the equation (La (nm) = (2.4 × 10 −10 )λ 4 (I D /I G ) −1 ), [27] the average domain size (La) of MDPC is calculated to be ≈13.42 nm, which is close to other reports on MOFs derived carbons with amorphous structure or heteroatom doping. [15,17,[19][20][21][22]28] The surface area and pore-size characterizations of as-prepared MDPC sample were performed by N 2 adsorption/desorption isotherms. A isotherm, as shown in Figure 2c, reveals the details of a high nitrogen uptake at the low-pressure region in which micropores filling occurs, as well as a hysteresis like type H4, at the middle and high-pressure region, which is indicative of the presence of large mesopores with broad size distribution embedded in a carbon matrix.…”
Section: Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…According to the equation (La (nm) = (2.4 × 10 −10 )λ 4 (I D /I G ) −1 ), [27] the average domain size (La) of MDPC is calculated to be ≈13.42 nm, which is close to other reports on MOFs derived carbons with amorphous structure or heteroatom doping. [15,17,[19][20][21][22]28] The surface area and pore-size characterizations of as-prepared MDPC sample were performed by N 2 adsorption/desorption isotherms. A isotherm, as shown in Figure 2c, reveals the details of a high nitrogen uptake at the low-pressure region in which micropores filling occurs, as well as a hysteresis like type H4, at the middle and high-pressure region, which is indicative of the presence of large mesopores with broad size distribution embedded in a carbon matrix.…”
Section: Resultsmentioning
confidence: 99%
“…[17,19] Although the role of heteroatom doping in carbonaceous materials is currently not fully understand, lots of experiments confirmed that heteroatoms dopants, including O, S, N, P, are considered as one of most efficient strategy to boost the potassium storage capacity of carbonaceous materials. [18][19][20][21][22] In this regard, well-designed carbonaceous material with an enlarged interlayer spacing, highly porous structure, and optimal heteroatom dopants is highly desired to overcome the limitations from the kinetics and capacity, and thus could boost the performance of PICs.…”
Section: Introductionmentioning
confidence: 99%
“…The first step toward achieving high‐performance K + ‐based energy storage technologies is to exploit host materials that have superior potassium storage capability and sufficient structural stability to withstand the repeated K + ‐ion insertion and extraction processes . For PIBs, the most representative K + ‐based rechargeable energy storage system, the aforementioned target indicates that developing efficient anode materials with the favorable features of high specific capacities, excellent cycling stabilities, and fast diffusion/reaction kinetics is urgently required to advance the progress of current PIBs toward practical applications . Inspired by the existing pioneering work involving graphite, tremendous efforts have been devoted to this area of research.…”
Section: Introductionmentioning
confidence: 99%
“…F might fully emit into the gaseous phase without being doped into the carbon work during thermal decomposition possibly due to the reactive and volatile nature of fluorine species. Some recent works [ 12 ] also show the difficulty of doping F into carbon while doping N and P is relatively easy. As a result, no F element can be identified.…”
Section: Resultsmentioning
confidence: 99%