2017
DOI: 10.1137/16m1099182
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Improved Bounds on Sidon Sets via Lattice Packings of Simplices

Abstract: Abstract.A B h set (or Sidon set of order h) in an Abelian group G is any subset {b0, b1, . . . , bn} of G with the property that all the sums bi 1 + · · · + bi h are different up to the order of the summands. Let φ(h, n) denote the order of the smallest Abelian group containing a B h set of cardinality n + 1. It is shown thatwhere δl(△ n ) is the lattice packing density of an n-simplex in Euclidean space. This determines the asymptotics exactly in cases where this density is known (n ≤ 3) and gives improved b… Show more

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Cited by 9 publications
(15 citation statements)
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“…The idea is to set l large enough so that the first summand on the right-hand side of (30) is minimized, but small enough so that the second summand is still negligible compared to the first one. Observe the relation (29) and the second summand on the right-hand side of (30). From (29) we see that, as n → ∞ and q ∼qn, the sum |△ q−1 n | = (see (34)), and since it has linearly many summands, there must exist λ ∈ (0, 1) such that q λn n−1 λn grows exponentially in n with the same exponent.…”
Section: Bounds and Asymptotics: Growing Alphabet Casementioning
confidence: 96%
See 3 more Smart Citations
“…The idea is to set l large enough so that the first summand on the right-hand side of (30) is minimized, but small enough so that the second summand is still negligible compared to the first one. Observe the relation (29) and the second summand on the right-hand side of (30). From (29) we see that, as n → ∞ and q ∼qn, the sum |△ q−1 n | = (see (34)), and since it has linearly many summands, there must exist λ ∈ (0, 1) such that q λn n−1 λn grows exponentially in n with the same exponent.…”
Section: Bounds and Asymptotics: Growing Alphabet Casementioning
confidence: 96%
“…Observe the relation (29) and the second summand on the right-hand side of (30). From (29) we see that, as n → ∞ and q ∼qn, the sum |△ q−1 n | = (see (34)), and since it has linearly many summands, there must exist λ ∈ (0, 1) such that q λn n−1 λn grows exponentially in n with the same exponent. By using Stirling's approximation, one can find the exponent of q λn n−1 λn as a function of λ, and check by differentiation that it is maximized for unique λ = λ * =q 1+q .…”
Section: Bounds and Asymptotics: Growing Alphabet Casementioning
confidence: 96%
See 2 more Smart Citations
“…. , bm} ⊆ G with the property that all its t-sums (b i 1 + · · · + b it ) are distinct, up to the order of the summands; see[24],[34].…”
mentioning
confidence: 99%