“…Assume that A is free with exponents (k, k + r), with r 0, k 1, that A has points of multiplicity 3 at most, and that not all lines of A pass through a point. Then the possible pairs (k, k + r) are (1, 1), (1, 2), (2, 2), (2, 3), (3,3), (3,4) or (4,4). In the last case, A has the combinatorial type of the dual Hesse arrangement.…”