2016
DOI: 10.1137/15m1036579
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Hybridization Number on Three Rooted Binary Trees is EPT

Abstract: Phylogenetic networks are leaf-labelled directed acyclic graphs that are used to describe non-treelike evolutionary histories and are thus a generalization of phylogenetic trees. The hybridization number of a phylogenetic network is the sum of all in-degrees minus the number of nodes plus one. The HYBRIDIZATION NUMBER problem takes as input a collection of rooted binary phylogenetic trees and asks to construct a phylogenetic network that contains an embedding of each of the input trees and has the smallest pos… Show more

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Cited by 17 publications
(21 citation statements)
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“…To see that these two minima can be different for a fixed set of phylogenetic trees, consider the set P of trees presented in Figure 2. It was shown in [13,15] that h(P) = 3 and that there are six phylogenetic networks each of which displays P and has a hybridisation number of three. However, none of these six phylogenetic networks is tree-child.…”
Section: Discussionmentioning
confidence: 99%
See 1 more Smart Citation
“…To see that these two minima can be different for a fixed set of phylogenetic trees, consider the set P of trees presented in Figure 2. It was shown in [13,15] that h(P) = 3 and that there are six phylogenetic networks each of which displays P and has a hybridisation number of three. However, none of these six phylogenetic networks is tree-child.…”
Section: Discussionmentioning
confidence: 99%
“…To illustrate, consider the two sets P and P of phylogenetic trees shown in Figure is a cherry-picking sequence for P of weight w(σ) = 12 − 8 = 4. In fact, it follows from [13,15] that h tc (P) = 4 (see Section 6 for details). On the other hand, σ = (5, z), (5,8), (4, z), (4, 1), (z, 3), (z, 6), (2, 3), (3, 1), (6, 7), (7,8), (1,8),…”
Section: Cherry-picking Characterisationsmentioning
confidence: 99%
“…For this, a fast exponential-time exact algorithm is needed, or a good heuristic. Although we have presented an O (n f (k) t) time algorithm for Hybridization Number, with n = |X| and t = |T |, it is not known if there exists an O (c n )-algorithm for some constant c. While O (c k n O (1) ) algorithms have been developed for instances consisting of two binary trees [28] and very recently for three binary trees [14], it is not clear if they exist for four or more binary trees, or for two or more nonbinary trees. Note that, for practical applications, the kernelization can also be combined with an efficient heuristic.…”
Section: Discussion and Open Problemsmentioning
confidence: 99%
“…While O(c k n O(1) ) algorithms have been developed for instances consisting of two binary trees [28] and very recently for three binary trees [14], it is not clear if they exist for four or more binary trees, or for two or more nonbinary trees. Note that, for practical applications, the kernelization can also be combined with an efficient heuristic.…”
Section: Discussion and Open Problemsmentioning
confidence: 99%