2011
DOI: 10.1215/ijm/1373636699
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HT90 and “simplest” number fields

Abstract: A standard formula (1) leads to a proof of HT90, but requires proving the existence of θ such that α = 0, so that β = α/σ(α).We instead impose the condition (M), that taking θ = 1 makes α = 0. Taking n = 3, we recover Shanks's simplest cubic fields. The "simplest" number fields of degrees 3 to 6, Washington's cyclic quartic fields, and a certain family of totally real cyclic extensions of Q(cos(π/4m)) all have defining polynomials whose zeroes satisfy (M).Further investigation of (M) for n = 4 leads to an elem… Show more

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Cited by 11 publications
(9 citation statements)
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“…Pairing-friendly curves have a special characteristic p, given by a polynomial p(x) of small degree evaluated at an integer u. For BLS12 curves, we have p(x) = (x 6 −2x 5 +2x 3 +x+1)/3, and for a 381-bit prime p, u = −(2 63 +2 62 +2 60 + 2 57 + 2 48 + 2 16 ) [7]. Joux and Pierrot introduced a dedicated polynomial selection that takes advantage of the polynomial form p = p(u) [25].…”
Section: Special Polynomial Selectionmentioning
confidence: 99%
See 1 more Smart Citation
“…Pairing-friendly curves have a special characteristic p, given by a polynomial p(x) of small degree evaluated at an integer u. For BLS12 curves, we have p(x) = (x 6 −2x 5 +2x 3 +x+1)/3, and for a 381-bit prime p, u = −(2 63 +2 62 +2 60 + 2 57 + 2 48 + 2 16 ) [7]. Joux and Pierrot introduced a dedicated polynomial selection that takes advantage of the polynomial form p = p(u) [25].…”
Section: Special Polynomial Selectionmentioning
confidence: 99%
“…We recall a variant of the Joux-Pierrot method to obtain a pair of polynomials (f y , g y ) admitting an automorphism, when k is not prime. First select an auxiliary polynomial with automorphism, for example from the list in [16].…”
Section: Special Polynomial Selectionmentioning
confidence: 99%
“…Indeed, the literature, e.g. [11], offers examples of polynomials g 0 , g 1 ∈ Q[x] and rational fractions A(x) ∈ Q(x) such that, for any number field K and any parameter a ∈ K, the polynomial g 0 + ag 1 admits A as a K-automorphism:…”
Section: Taking Advantage Of Automorphismsmentioning
confidence: 99%
“…M.N.Gras [9], [10], V.Ennola [2], [3] and A.J.Lazarus [18] investigated the unit group of the simplest fields. K.Foster [4] obtained the simplest parametric polynomials, just by using a special identity of units in cyclic extensions. It shows, that these fields have some other unique and interesting properties.…”
Section: Introductionmentioning
confidence: 99%