How to construct a triangular matrix of a given order

$(k+1)$-potent Matrices in triangular matrix Groups and Incidence Algebras of Finite Posets

“…In the section 5 we present an important remark and we compare our approach with the result obtain by Slowik in [3].…”

Coninvolutions on Upper Triangular Matrix Group over the Ring of Gaussian Integers and Quaternions integers modulo $p$

“…with arbitrary z 2 , z 3 , z 4 ∈ Z p . If Z rr = Z ss with s > r + 1 then, from the system (7), necessarily B = C = 0 and A = D. Here we obtain the equation…”

“…The cases (ii),(iii) and (iv) solves similarly. (v) In this case we have that a = x, b = y, c = w and d = z, then from system (7), we have B = 0. From first and fourth equations into the same system we obtain…”

“…2b.) In the case that Z rr = Z ss we study the following cases: 8) and the third equation of the system (7) we obtain the new following system…”

“…2 n 2 − s i=1 n 2 i , and using the Slowik's formula (see [7]) we can simplify the above formula for CI(n, Z p [i, j, k]). Table 1…”