“…Since M is strictly unitary, the equations in (19) and (22) give the normalization conditions h(a, 1, b) = 0 = h(1, a, b) = h(a, b, 1) for h, while the equations in (23) imply the normalization conditions µ(a, 1) = 0 = µ(1, a) for µ. Thus, (h, µ) ∈ C 3 c (M, A) is a commutative three-cochain, which is actually a three-cocycle, since the coherence conditions (18), (20) and (21) Since an easy comparison (see Example 4.1) shows that M = A h,µ M , the proof of this part is complete, under the hypothesis of being M totally disconnected and strictly unitary.…”