2005
DOI: 10.1016/j.jmaa.2004.12.007
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Hilbert space structure and positive operators

Abstract: Let X be a real Banach space. We prove that the existence of an injective, positive, symmetric and not strictly singular operator from X into its dual implies that either X admits an equivalent Hilbertian norm or it contains a nontrivially complemented subspace which is isomorphic to a Hilbert space. We also treat the non-symmetric case

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Cited by 9 publications
(7 citation statements)
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“…for ∀ ∈ and elements of field. In (Casazza, Fickus, Mixon, & Peterson, 2013;Drivaliaris & Yannakakis, 2005), it is said that consequence of Theorem 3 is as follows A real Banach space is isomorphic to a Hilbert space if and only if there is an isomorphism : → ′ that is positive and symmetric.…”
Section: Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…for ∀ ∈ and elements of field. In (Casazza, Fickus, Mixon, & Peterson, 2013;Drivaliaris & Yannakakis, 2005), it is said that consequence of Theorem 3 is as follows A real Banach space is isomorphic to a Hilbert space if and only if there is an isomorphism : → ′ that is positive and symmetric.…”
Section: Resultsmentioning
confidence: 99%
“…The use of space ℓ is intended to have distinction on = 2 and > 2. Proceeding of ICSA 2019, p: 51-56 ISBN 978-979-19256-3-1 (PDF) 53 At (Drivaliaris & Yannakakis, 2005), it is said that let is a normed space with norm ‖•‖ and ′ is the dual space of the X and 〈•,•〉 is their duality product. The following definitions are explanations of the duality product, as follows: Definition 1.…”
Section: Methodsmentioning
confidence: 99%
“…It is well-known from [4] (see also [2]) that Theorem 1. A Banach space X has the property that there exists a strongly positive operator P from X onto X * such that P x, x ≥ θ x 2 for some θ > 0, if and only if, the Banach space X is isomorphic to a Hilbert space.…”
Section: Preliminariesmentioning
confidence: 99%
“…(ii) This inequality is derived in passing in [10]. Consider ϕ ∈ X * , for any ε > 0 there is a normalized element g ∈ X such that ϕ, g ≥ (1 − ε) ϕ since ϕ = sup x∈X, x =1 ϕ, x .…”
Section: Topologies and Continuitymentioning
confidence: 99%