2015
DOI: 10.1039/c5ra07306e
|View full text |Cite
|
Sign up to set email alerts
|

Highly enterprising calcium zirconium phosphate [CaZr4(PO4)6:Dy3+, Ce3+] phosphor for white light emission

Abstract: A series of CaZr4(PO4)6:Dy3+, CaZr4(PO4)6:Ce3+ and CaZr4(PO4)6:Dy3+, Ce3+ phosphors were prepared by the solid state reaction process.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1

Citation Types

0
40
0

Year Published

2015
2015
2019
2019

Publication Types

Select...
9

Relationship

8
1

Authors

Journals

citations
Cited by 100 publications
(40 citation statements)
references
References 45 publications
(40 reference statements)
0
40
0
Order By: Relevance
“…From Figure , a spectral overlap between the emission spectrum of Ce 3+ and the excitation spectrum of Tb 3+ can be seen. The prime condition for the energy transfer to take place is that there should be a spectral overlap between the emission and excitation spectra of sensitizers and activators, respectively . The Ce 3+ ions when excited by 279 nm emits in the broad band ranging from 300 to 400 nm, which is the excitation region for Tb 3+ ions as shown in Figure .…”
Section: Resultsmentioning
confidence: 99%
“…From Figure , a spectral overlap between the emission spectrum of Ce 3+ and the excitation spectrum of Tb 3+ can be seen. The prime condition for the energy transfer to take place is that there should be a spectral overlap between the emission and excitation spectra of sensitizers and activators, respectively . The Ce 3+ ions when excited by 279 nm emits in the broad band ranging from 300 to 400 nm, which is the excitation region for Tb 3+ ions as shown in Figure .…”
Section: Resultsmentioning
confidence: 99%
“…This finding implies that Dy 3+ ions occupy more non‐central symmetrical sites in Sr 1.925–1.5y P 2 O 7 :0.05Dy 3+ ,yCe 3+ phosphors. Co‐doping of Ce 3+ ion is responsible for changes in local sites around the Dy 3+ ion from higher to lower symmetry, under 307 nm UV excitation …”
Section: Resultsmentioning
confidence: 99%
“…Taking a point on the initial rise side of an isolated TL peak, a tangent is drawn at the point ( N ≡ Ic, Tc) (Figure ) and the slope was calculated. It is assumed that I(T) has the form (initial rise region): normalI(),t=normalcexp(),normalEtrue/kT where, c is the constant.…”
Section: Resultsmentioning
confidence: 99%