1990
DOI: 10.1016/0022-247x(90)90204-s
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Higher integrability results and Hölder continuity

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Cited by 3 publications
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“…Let η 1 ∈ (0, 1) be the root of the equation η = ((f α ) I ) 1/α , cf. (3). It is easily seen that this equation is solvable and the root is unique.…”
Section: Gurov-reshetnyak Inequality For Power Functions On the Real mentioning
confidence: 94%
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“…Let η 1 ∈ (0, 1) be the root of the equation η = ((f α ) I ) 1/α , cf. (3). It is easily seen that this equation is solvable and the root is unique.…”
Section: Gurov-reshetnyak Inequality For Power Functions On the Real mentioning
confidence: 94%
“…Fix an ε ∈ (0, 2). Set p = p(ε) = p + R (ε) > 1, α = α(ε) = 1/(p(ε) − 1) and define η 1 = η 1 (ε) by (3). According to Theorem 2.1 and Corollary 2.4, one has Table 1 shows some values of the parameters mentioned obtained in numerical experiments, where the columns 6 and 8 contain the maximum points of the function ψ 0 (α, η) for α = 1/(p − 1) and α = −1/p, correspondingly.…”
Section: Numerical Experiments Examples and Commentsmentioning
confidence: 99%
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