“…If ω j 1 < 6, then at least one unit of the resource is wasted in the interval [0, 1), and at least one unit is lost in the interval [1,2). Thus, ω j 1 = 6, j 1 = 1, and this job completes on M 2 at time C 2 1 = 2, as otherwise at least 6 units of the resource would be wasted in the interval [1,2). Similarly, let j 2 be the second job in σ .…”