2014
DOI: 10.1090/s0002-9939-2014-12149-6
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Heegaard Floer homology of some Mazur type manifolds

Abstract: Abstract. We show that an infinite family of contractible 4-manifolds have the same boundary as a special type of plumbing. Consequently their Ozsváth-Szabó invariants can be calculated algorithmically. We run this algorithm for the first few members of the family and list the resulting Heegaard-Floer homologies. We also show that the rank of the Heegaard-Floer homology can get arbitrary large values in this family by using its relation with the Casson invariant. For comparison, we list the ranks of Floer homo… Show more

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Cited by 10 publications
(8 citation statements)
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“…A simple isotopy gives the third diagram, and the aforementioned handle moves give the last diagram of X Ln . Corollary 1.7 in [7] and the last diagram thus tells that the Casson invariant λ(∂X Ln ) of the boundary 3-manifold is equal to −2. Therefore each X Ln is not homeomorphic to D 4 .…”
Section: Figure 20 X Lnmentioning
confidence: 96%
“…A simple isotopy gives the third diagram, and the aforementioned handle moves give the last diagram of X Ln . Corollary 1.7 in [7] and the last diagram thus tells that the Casson invariant λ(∂X Ln ) of the boundary 3-manifold is equal to −2. Therefore each X Ln is not homeomorphic to D 4 .…”
Section: Figure 20 X Lnmentioning
confidence: 96%
“…4 However, the above type of conjecture fails for non Seifert fibered plumbed homology spheres. The first examples were provided by Maruyama [Mar82], independently refound by Akbulut and Karakurt [AK14]. These manifolds are not Seifert fibered 5 unless n = 1 and they can be realized as the boundary of a plumbing graph with two nodes and five branches, and are reproven via our approach.…”
Section: Introductionmentioning
confidence: 95%
“…Note that the star-shaped plumbing graph associated to a Seifert manifold can always be drawn such that no vertices are bad except possibly the central one. We'll briefly describe the algorithm; see [AK12] for a very concrete user's guide. Let Γ be the plumbing graph and let X(Γ) denote the associated plumbed 4-manifold.…”
Section: Némethi's Algorithmmentioning
confidence: 99%
“…I would like to thank Ç agri Karakurt for introducing me to Némethi's graded roots during his visit to Rice in Spring 2012 (and he and his coauthor for the useful primer in [AK12]). I would also like to thank Tye Lidman for some helpful conversations.…”
Section: Acknowledgementsmentioning
confidence: 99%
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