2016
DOI: 10.1090/tran/6894
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Hard Lefschetz property of symplectic structures on compact Kähler manifolds

Abstract: In this paper, we give a new method to construct a compact symplectic manifold which does not satisfy the hard Lefschetz property. Using our method, we construct a simply connected compact Kähler manifold (M, J, ω) and a symplectic form σ on M which does not satisfy the hard Lefschetz property, but is symplectically deformation equivalent to the Kähler form ω. As a consequence, we can give an answer to the question posed by Khesin and Mc-Duff as follows. According to symplectic Hodge theory, any symplectic for… Show more

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Cited by 5 publications
(12 citation statements)
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“…Equality (ii) in the above proposition means that the behaviour of the symplectic invariantχ (8), which also gives a resolution of the same Lefschetz maps, one immediately concludes that the cohomologyȞ * (k) (M ) is isomorphic to the (k − 1)-filtered cohomology as follows:…”
Section: Extension Of the Generalized Coeffective Complexesmentioning
confidence: 80%
See 2 more Smart Citations
“…Equality (ii) in the above proposition means that the behaviour of the symplectic invariantχ (8), which also gives a resolution of the same Lefschetz maps, one immediately concludes that the cohomologyȞ * (k) (M ) is isomorphic to the (k − 1)-filtered cohomology as follows:…”
Section: Extension Of the Generalized Coeffective Complexesmentioning
confidence: 80%
“…Proof. Let us first recall that Cho proves in [8,Theorem 1.3] the existence of a compact Kähler manifold (X, ω) with dim C X = 3 such that (1) X is simply-connected,…”
Section: Proof Notice First Thatčmentioning
confidence: 99%
See 1 more Smart Citation
“…It is known that the hard Lefschetz property does not hold in general. See [Cho1] or [Go] for example. However, it is not known whether (M, ω) satisfies the hard Lefschetz property when (M, ω) admits a Hamiltonian torus action with isolated fixed points.…”
Section: Introductionmentioning
confidence: 99%
“…In the symplectic category, there are a lot of examples which do not satisfy the hard Lefschetz theorem so that the unimodality of Betti numbers is not obvious in general. (See [3], [5], and [7]).…”
Section: Introductionmentioning
confidence: 99%