2004
DOI: 10.1016/s0166-8641(03)00182-2
|View full text |Cite
|
Sign up to set email alerts
|

Hamiltonian knot projections and lengths of thick knots

Abstract: For a knot or link K, L(K) denotes the rope length of K and Cr(K) denotes the crossing number of K. An important problem in geometric knot theory concerns the bound on L(K) in terms of Cr(K). It is well known that there exist positive constants c 1 , c 2 such that for any knot or link K, c 1 • (Cr(K)) 3/4 ≤ L(K) ≤ c 2 • (Cr(K)) 2 . In this paper, we prove that there exists a constant c > 0 such that for any knot or link K, L(K) ≤ c • (Cr(K)) 3/2 . This is done through the study of regular projections of knots … Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
2

Citation Types

1
51
0

Year Published

2006
2006
2024
2024

Publication Types

Select...
6

Relationship

1
5

Authors

Journals

citations
Cited by 22 publications
(52 citation statements)
references
References 23 publications
(11 reference statements)
1
51
0
Order By: Relevance
“…It follows that K can be realized by a smooth knot of unit thickness with length at most b 1 ·(Cr(K)) 3/2 whose total curvature is bounded above by b 2 ·Cr(K) for some constant b 2 > 0. For details of the embedding construction we refer to [15]. This proves (i).…”
Section: ·2 the Case Of τ Msupporting
confidence: 55%
See 2 more Smart Citations
“…It follows that K can be realized by a smooth knot of unit thickness with length at most b 1 ·(Cr(K)) 3/2 whose total curvature is bounded above by b 2 ·Cr(K) for some constant b 2 > 0. For details of the embedding construction we refer to [15]. This proves (i).…”
Section: ·2 the Case Of τ Msupporting
confidence: 55%
“…The proof of (i) relies on the lattice embedding of K on the cubic lattice as described in [15] and Theorem 2·5. It is proven in [15] that there exists a constant b 1 > 0 such that any knot type K can be embedded in the cubic lattice with a length at most b 1 (Cr(K)) 3/2 . Furthermore, the total curvature of such an embedding is of the order O(Cr(K)).…”
Section: ·2 the Case Of τ Mmentioning
confidence: 99%
See 1 more Smart Citation
“…(This aspect of the problem has been addressed in many papers (see e.g. [3,4], and the references there); the solutions proposed in those papers appear under the denominations "ideal knot," "tight knot," "fat knot," "knot of minimal rope length," and so on.) In the present paper, we discuss the aesthetic merits and shortcomings of the normal forms obtained.…”
Section: Introductionmentioning
confidence: 99%
“…The case of upper bounds turns out to be harder and no sharp upper bounds have been found in general at the writing of this paper. The best upper bound known for the ropelength of any knot K is of the order O((Cr(K)) 3/2 ) [11]. However, it is not known whether this bound is sharp (it is generally believed that it is not).…”
Section: Introductionmentioning
confidence: 99%