2009
DOI: 10.1007/s00493-009-2362-0
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Hamilton cycles in highly connected and expanding graphs

Abstract: In this paper we prove a sufficient condition for the existence of a Hamilton cycle, which is applicable to a wide variety of graphs, including relatively sparse graphs. In contrast to previous criteria, ours is based on only two properties: one requiring expansion of "small" sets, the other ensuring the existence of an edge between any two disjoint "large" sets. We also discuss applications in positional games, random graphs and extremal graph theory.

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Cited by 45 publications
(62 citation statements)
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References 22 publications
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“…The next lemma is a slight strengthening of Claim 2.2 from [13] with a similar proof. It shows that in any graph having the small and large expansion properties for any path P 0 and its endpoint v 1 many other endpoints can be created by a small number of rotations with fixed endpoint v 1 .…”
Section: Proofmentioning
confidence: 66%
See 1 more Smart Citation
“…The next lemma is a slight strengthening of Claim 2.2 from [13] with a similar proof. It shows that in any graph having the small and large expansion properties for any path P 0 and its endpoint v 1 many other endpoints can be created by a small number of rotations with fixed endpoint v 1 .…”
Section: Proofmentioning
confidence: 66%
“…We obtain the corresponding sets Z and U = V \ (D ∪ Z) and conclude that the induced graph G[U ] satisfies the small expansion property S(s/2, g/2). Theorem 2.5 from [13] states that for every choice of the expansion parameter r with 12 ≤ r ≤ √ n, every n-vertex graph G satisfying S r, n ln r r ln n and L n ln r 1035 ln n is Hamiltonian. Hence, applying this statement to G[U ] with s = n α , g = 4αn/n α and r = n α /2, we see that G[U ] is Hamiltonian.…”
Section: Proofmentioning
confidence: 99%
“…We will use the following special case of a theorem from [11]: Then G is hamiltonian, for sufficiently large n.…”
Section: Enforcing a Hamilton Cyclementioning
confidence: 99%
“…a Hamilton path between any given pair of vertices in a random graph. This can be achieved using known tools (say, those from [13]). Here too the constant C 2 = C 2 (α) has to grow as α → 0.…”
Section: Introductionmentioning
confidence: 99%